ECHO_content/ECHO_resource.py - diff

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version 1.2, 2008/12/17 12:12:27	version 1.3, 2009/04/14 16:31:27
Line 204 class ECHO_resource(CatalogAware,Folder,	Line 204 class ECHO_resource(CatalogAware,Folder,

def getRDF(self,urn=None):	def getRDF(self,urn=None):
"""rdf"""	"""rdf"""
ret=getRDFDescription(self,self.link,urn=urn)	ap = self.getArchivePathFromMetadata()


	ret=getRDFDescription(self,self.link,urn=urn,ap=ap)
	logging.debug("ret:"+repr(ret))
return ret+self.createSubElementRDF(urn=urn)	return ret+self.createSubElementRDF(urn=urn)


Line 648 class ECHO_resource(CatalogAware,Folder,	Line 652 class ECHO_resource(CatalogAware,Folder,
"""gibt pfad zum image aus"""	"""gibt pfad zum image aus"""
return self.getImageView(noredirect="yes",onlyPath="yes")	return self.getImageView(noredirect="yes",onlyPath="yes")

	def getArchivePathFromMetadata(self):
	try:
	fh=ECHO_helpers.urlopen(self.metalink)
	dom=xml.dom.minidom.parse(fh)
	archivePath=dom.getElementsByTagName('archive-path')
	text = getText(archivePath[0].childNodes)
	return text
	except:
	return ""

def getImageView(self,noredirect=None,onlyPath=None):	def getImageView(self,noredirect=None,onlyPath=None):
"""getImages; give Imageviewr and <error></error> if somthing goes wrong."""	"""getImages; give Imageviewr and <error></error> if somthing goes wrong."""
try:	try: